WebMay 30, 2024 · Distance between two towers = 100 m Height of second tower = 120 m Angular depression = 45° Formula Used: Tan θ = H/B Where, H = Hypotenuse B = base Calculation: Let the length of first tower (CD) be h ⇒ AE = AB - EB ⇒ AE = 120 - h In the above figure BC = ED = 100m According to the question, we have In ΔAED, Tan 45° = AE/ED ⇒ 1 … WebFeb 12, 2024 · From the top of a tower of 100m height, a ball is dropped and at the same time another ball is projected vertically upwards from the ground with a velocity of 25ms-1. Find when and where the two balls will meet. Take g = 9.8 ms-2. motion in a plane class-11 1 Answer +2 votes answered Feb 12, 2024 by KhusbuKumari (51.4k points)
A stone is allowed to fall from the top of a tower 100 m high and …
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The height of a tower is 100 m. When the angle of elevation of the sun
WebLet AB be tower and AB = 100 m and angles of elevation of A at C and D are 30° and 45° respectively and CD = x. Let BD = y. Now in right Δ A D B, tan θ = Perpendicular Base = A B D B tan 45 ∘ = 100 y ⇒ 1 = 100 y ⇒ y = 100 Similarly in right Δ A C B, tan 30 ∘ = A B C B ⇒ 1 3 = 100 y + x ⇒ 1 3 = 100 100 + x ⇒ 100 + x = 100 3 ... WebMay 31, 2024 · The height of a tower is 100 m. When the angle of elevation of the sun changes from 30° to 45°, the shadow of the tower becomes x metres less. The value of x is A. 100 m B. 100√3 100 3 m C. 100(√3 − 1) 100 ( 3 − 1) m D. 100 √3 100 3 m trigonometry class-10 1 Answer +1 vote answered May 31, 2024 by Saadah (31.4k points) WebA stone is allowed to fall from the top of a tower 100 m high and at the same time another stone is projected vertically upwards from the ground with a velocity of 25 m/s. ... okay initially the u the velocity will be 25 meter per second and the distance traveled is 100 minus x because the height of the tower is 100 meter so we can minus the ... helaman 12 lds